What are the solutions to the equation 9x^2+x-8=0 ?

The solutions to the equation 9x^2+x-8=0 are x= 8/9 ,x=-1

Find the zeros of 9x^2+x-8=0

The zeros of 9x^2+x-8=0 are x= 8/9 ,x=-1

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9 x^{2} + x - 8 = 0

x = \frac{8}{9}, x = - 1

Solution steps

9 x^{2} + x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 9 ( - 8 )}{2 \cdot 9}

1^{2} - 4 \cdot 9 (- 8) = 17

x_{1, 2} = \frac{- 1 \pm 17}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 1 + 17}{2 \cdot 9}, x_{2} = \frac{- 1 - 17}{2 \cdot 9}

x = \frac{- 1 + 17}{2 \cdot 9} : \frac{8}{9}

x = \frac{- 1 - 17}{2 \cdot 9} : - 1

The solutions to the quadratic equation are:

x = \frac{8}{9}, x = - 1

4^{∣ x ∣} = 128

5 u^{2} - 3 u + 2 = 0

\frac{2}{4} + \frac{3}{4}

5 x p + 5 x

What are the solutions to the equation 9x^2+x-8=0 ?
The solutions to the equation 9x^2+x-8=0 are x= 8/9 ,x=-1
Find the zeros of 9x^2+x-8=0
The zeros of 9x^2+x-8=0 are x= 8/9 ,x=-1