What is (8x^2y^3-6x^3y)/(2x^2y) ?

The solution to (8x^2y^3-6x^3y)/(2x^2y) is 4y^2-3x

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simplify (8x^2y^3-6x^3y)/(2x^2y)

simplify

\frac{8 x ^{2} y ^{3} - 6 x ^{3} y}{2 x ^{2} y}

4 y^{2} - 3 x

Solution steps

\frac{8 x ^{2} y ^{3} - 6 x ^{3} y}{2 x ^{2} y}

Factor

8 x^{2} y^{3} - 6 x^{3} y : 2 x^{2} y (4 y^{2} - 3 x)

= \frac{2 x ^{2} y ( 4 y ^{2} - 3 x )}{2 x ^{2} y}

Cancel the common factor:

2

= \frac{x ^{2} y ( 4 y ^{2} - 3 x )}{x ^{2} y}

Cancel the common factor:

x^{2}

= \frac{y ( 4 y ^{2} - 3 x )}{y}

Cancel the common factor:

y

= 4 y^{2} - 3 x

- x^{2} + 5 x - 7 = 0

4125

2 x^{3} + 4 x^{2} + x + 2

1 0^{0.2}

4 x^{2} - 6 x + 1 = 0

What is (8x^2y^3-6x^3y)/(2x^2y) ?
The solution to (8x^2y^3-6x^3y)/(2x^2y) is 4y^2-3x