What is factor 216p^3+125q^3 ?

The solution to factor 216p^3+125q^3 is (6p+5q)(36p^2-30pq+25q^2)

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factor 216p^3+125q^3

factor

216 p^{3} + 125 q^{3}

(6 p + 5 q) (36 p^{2} - 30 pq + 25 q^{2})

Solution steps

216 p^{3} + 125 q^{3}

Apply exponent rules

= (6 p)^{3} + (5 q)^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(6 p)^{3} + (5 q)^{3} = (6 p + 5 q) ((6 p)^{2} - 6 p \cdot 5 q + (5 q)^{2})

= (6 p + 5 q) ((6 p)^{2} - 6 p \cdot 5 q + (5 q)^{2})

Simplify

(6 p)^{2} - 6 p \cdot 5 q + (5 q)^{2} : 36 p^{2} - 30 pq + 25 q^{2}

= (6 p + 5 q) (36 p^{2} - 30 pq + 25 q^{2})

(x + 8)^{2} - 4 (x + 8) - 1

∣ 4 - 8 ∣

\frac{- 6}{- 9}

3 (p - 2 q) - 4 (2 p - 3 q - 5)

4 + 6 (a c + 2 b) + 2 a c

What is factor 216p^3+125q^3 ?
The solution to factor 216p^3+125q^3 is (6p+5q)(36p^2-30pq+25q^2)