What are the solutions to the equation 4x^2-28x=0 ?

The solutions to the equation 4x^2-28x=0 are x=7,x=0

Find the zeros of 4x^2-28x=0

The zeros of 4x^2-28x=0 are x=7,x=0

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4 x^{2} - 28 x = 0

x = 7, x = 0

Solution steps

4 x^{2} - 28 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 28)^{2} - 4 \cdot 4 \cdot 0 = 28

x_{1, 2} = \frac{- ( - 28 ) \pm 28}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 28 ) + 28}{2 \cdot 4}, x_{2} = \frac{- ( - 28 ) - 28}{2 \cdot 4}

x = \frac{- ( - 28 ) + 28}{2 \cdot 4} : 7

x = \frac{- ( - 28 ) - 28}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

x = 7, x = 0

a^{4} - 625

\frac{4}{7} - \frac{1}{5}

\frac{9}{8} \times \frac{7}{8}

d^{2} + 16 = 60

\frac{1}{3} - \frac{1}{1}

What are the solutions to the equation 4x^2-28x=0 ?
The solutions to the equation 4x^2-28x=0 are x=7,x=0
Find the zeros of 4x^2-28x=0
The zeros of 4x^2-28x=0 are x=7,x=0