What is (x+4)^2+(x-4)^2 ?

The solution to (x+4)^2+(x-4)^2 is 2x^2+32

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simplify (x+4)^2+(x-4)^2

simplify

(x + 4)^{2} + (x - 4)^{2}

2 x^{2} + 32

Solution steps

(x + 4)^{2} + (x - 4)^{2}

Expand

(x + 4)^{2} : x^{2} + 8 x + 16

= x^{2} + 8 x + 16 + (x - 4)^{2}

Expand

(x - 4)^{2} : x^{2} - 8 x + 16

= x^{2} + 8 x + 16 + x^{2} - 8 x + 16

Group like terms

= x^{2} + x^{2} + 8 x - 8 x + 16 + 16

Add similar elements:

x^{2} + x^{2} = 2 x^{2}

= 2 x^{2} + 8 x - 8 x + 16 + 16

Add similar elements:

8 x - 8 x = 0

= 2 x^{2} + 16 + 16

Add the numbers:

16 + 16 = 32

= 2 x^{2} + 32

\frac{x}{tan ( x )}

\frac{9}{10} + \frac{1}{2}

(3 x^{4 a - 5} + 2 y^{2 a + 1})^{2}

\frac{3 x - 3}{x - 1}

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