What is (2x^2+7x+10)-(x^2+2x-9) ?

The solution to (2x^2+7x+10)-(x^2+2x-9) is x^2+5x+19

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simplify (2x^2+7x+10)-(x^2+2x-9)

simplify

(2 x^{2} + 7 x + 10) - (x^{2} + 2 x - 9)

x^{2} + 5 x + 19

Solution steps

(2 x^{2} + 7 x + 10) - (x^{2} + 2 x - 9)

Apply rule:

(a) = a

(2 x^{2} + 7 x + 10) = 2 x^{2} + 7 x + 10

= 2 x^{2} + 7 x + 10 - (x^{2} + 2 x - 9)

Apply the distributive law:

- (a + b) = - a - b

- (x^{2} + 2 x - 9) = - x^{2} - 2 x + 9

= 2 x^{2} + 7 x + 10 - x^{2} - 2 x + 9

Group like terms

= 2 x^{2} - x^{2} + 7 x - 2 x + 10 + 9

Add similar elements:

2 x^{2} - x^{2} = x^{2}

= x^{2} + 7 x - 2 x + 10 + 9

Add similar elements:

7 x - 2 x = 5 x

= x^{2} + 5 x + 10 + 9

Add the numbers:

10 + 9 = 19

= x^{2} + 5 x + 19

(- 6 x^{2} - 10 x + 4) - (8 x^{2} - 8 x)

n^{2} (n + 4)^{2} - 9 n (n + 4)

9 x^{2} + 4 x - (- 4) x^{2} - 7

(9 - 3 i) - (5 i - 8)

\frac{4}{3} - \frac{4}{3}

What is (2x^2+7x+10)-(x^2+2x-9) ?
The solution to (2x^2+7x+10)-(x^2+2x-9) is x^2+5x+19