What is n^2(n+4)^2-9n(n+4) ?

The solution to n^2(n+4)^2-9n(n+4) is n^4+8n^3+7n^2-36n

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simplify n^2(n+4)^2-9n(n+4)

simplify

n^{2} (n + 4)^{2} - 9 n (n + 4)

n^{4} + 8 n^{3} + 7 n^{2} - 36 n

Solution steps

n^{2} (n + 4)^{2} - 9 n (n + 4)

Expand

n^{2} (n + 4)^{2} : n^{4} + 8 n^{3} + 16 n^{2}

= n^{4} + 8 n^{3} + 16 n^{2} - 9 n (n + 4)

Expand

- 9 n (n + 4) : - 9 n^{2} - 36 n

= n^{4} + 8 n^{3} + 16 n^{2} - 9 n^{2} - 36 n

Add similar elements:

16 n^{2} - 9 n^{2} = 7 n^{2}

= n^{4} + 8 n^{3} + 7 n^{2} - 36 n

9 x^{2} + 4 x - (- 4) x^{2} - 7

(9 - 3 i) - (5 i - 8)

\frac{4}{3} - \frac{4}{3}

(3 x^{- 2} y^{- 3})^{- 4}

\frac{9}{10} - \frac{1}{10}

What is n^2(n+4)^2-9n(n+4) ?
The solution to n^2(n+4)^2-9n(n+4) is n^4+8n^3+7n^2-36n