What are the solutions to the equation 2m^2-m-3=0 ?

The solutions to the equation 2m^2-m-3=0 are m= 3/2 ,m=-1

Find the zeros of 2m^2-m-3=0

The zeros of 2m^2-m-3=0 are m= 3/2 ,m=-1

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2 m^{2} - m - 3 = 0

m = \frac{3}{2}, m = - 1

Decimal Notation

m = 1.5, m = - 1

Solution steps

2 m^{2} - m - 3 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 3) = 5

m_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 2}

Separate the solutions

m_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 2}, m_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 2}

m = \frac{- ( - 1 ) + 5}{2 \cdot 2} : \frac{3}{2}

m = \frac{- ( - 1 ) - 5}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

m = \frac{3}{2}, m = - 1

x^{2} - 8 x + 16 \geq 0

∣ 6 ∣ - 7

\frac{3}{4} x - \frac{1}{6} = \frac{2}{3}

(x^{\frac{1}{4}})^{4}

1 - \frac{1}{1 - \frac{1}{1 - \frac{2}{5}}}

What are the solutions to the equation 2m^2-m-3=0 ?
The solutions to the equation 2m^2-m-3=0 are m= 3/2 ,m=-1
Find the zeros of 2m^2-m-3=0
The zeros of 2m^2-m-3=0 are m= 3/2 ,m=-1