What is (-4pq^5r^3)/(8p^2q^2r^{10)} ?

The solution to (-4pq^5r^3)/(8p^2q^2r^{10)} is -(q^3)/(2pr^7)

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simplify (-4pq^5r^3)/(8p^2q^2r^{10)}

simplify

\frac{- 4 p q ^{5} r ^{3}}{8 p ^{2} q ^{2} r ^{10}}

- \frac{q ^{3}}{2 p r ^{7}}

Solution steps

\frac{- 4 p q ^{5} r ^{3}}{8 p ^{2} q ^{2} r ^{10}}

Factor the number:

8 = 4 \cdot 2

= \frac{- 4 p q ^{5} r ^{3}}{4 \cdot 2 p ^{2} q ^{2} r ^{10}}

Cancel the common factor:

4

= \frac{- p q ^{5} r ^{3}}{2 p ^{2} q ^{2} r ^{10}}

Simplify

\frac{q ^{5}}{q ^{2}} : q^{3}

= \frac{- p q ^{3} r ^{3}}{2 p ^{2} r ^{10}}

Simplify

\frac{p}{p ^{2}} : \frac{1}{p}

= \frac{- q ^{3} r ^{3}}{2 p r ^{10}}

Simplify

\frac{r ^{3}}{r ^{10}} : \frac{1}{r ^{7}}

= \frac{- q ^{3}}{2 p r ^{7}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{q ^{3}}{2 p r ^{7}}

\frac{5}{8} - \frac{6}{8}

s^{2} + 6 s + 25 = 0

1 < 3

- \frac{1}{4} - 4

8 \leq ∣ 4 x - 8 ∣

What is (-4pq^5r^3)/(8p^2q^2r^{10)} ?
The solution to (-4pq^5r^3)/(8p^2q^2r^{10)} is -(q^3)/(2pr^7)