What is (m^2+2mn)-(mn+n^2) ?

The solution to (m^2+2mn)-(mn+n^2) is m^2+mn-n^2

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simplify (m^2+2mn)-(mn+n^2)

simplify

(m^{2} + 2 mn) - (mn + n^{2})

m^{2} + mn - n^{2}

Solution steps

(m^{2} + 2 mn) - (mn + n^{2})

Apply rule:

(a) = a

(m^{2} + 2 mn) = m^{2} + 2 mn

= m^{2} + 2 mn - (mn + n^{2})

Apply the distributive law:

- (a + b) = - a - b

- (mn + n^{2}) = - mn - n^{2}

= m^{2} + 2 mn - mn - n^{2}

Add similar elements:

2 mn - mn = mn

= m^{2} + mn - n^{2}

x^{2} + 5 x + 2 x + 10

- \frac{1}{2} + (- \frac{4}{9})

4 i^{3} - 2 i^{2} + 1

(3 - 2 i) + [(4 - 5 i) - (5 + i)]

(1 + 2 i) + (2 - 3 i)