What is (2+3i)+(4-2i) ?

The solution to (2+3i)+(4-2i) is 6+i

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simplify (2+3i)+(4-2i)

simplify

(2 + 3 i) + (4 - 2 i)

6 + i

Solution steps

(2 + 3 i) + (4 - 2 i)

Group the real part and the imaginary part of the complex number

(a + bi) + (c + d i) = (a + c) + (b + d) i

= (2 + 4) + (3 - 2) i

Simplify

(2 + 4) + (3 - 2) i : 6 + i

= 6 + i

\frac{72}{25}

(z + 1)^{4}

x^{4} + x^{- 4}

(x + 2 y + 3)^{3}

3 x (x - 2) + 7 (2 - x)