What is expand (x+2)(x-3)(x-2)(x+3) ?

The solution to expand (x+2)(x-3)(x-2)(x+3) is x^4-13x^2+36

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expand (x+2)(x-3)(x-2)(x+3)

expand

(x + 2) (x - 3) (x - 2) (x + 3)

x^{4} - 13 x^{2} + 36

Solution steps

(x + 2) (x - 3) (x - 2) (x + 3)

Expand

(x + 2) (x - 3) (x - 2) (x + 3) : (x^{2} - 4) (x - 3) (x + 3)

= (x^{2} - 4) (x - 3) (x + 3)

Apply Difference of Two Squares

(x - 3) (x + 3) : x^{2} - 9

= (x^{2} - 4) (x^{2} - 9)

Apply FOIL method

(x^{2} - 4) (x^{2} - 9) : x^{4} - 13 x^{2} + 36

= x^{4} - 13 x^{2} + 36

(- 3.2) (9.6)

\frac{3}{9} + \frac{4}{9}

6 \cdot \frac{3}{22}

2 d^{3} - 4 d^{2} - 8 d + 16

\frac{a ^{3}}{a ^{3}}

What is expand (x+2)(x-3)(x-2)(x+3) ?
The solution to expand (x+2)(x-3)(x-2)(x+3) is x^4-13x^2+36