What are the solutions to the equation 3x^2-19x+20=0 ?

The solutions to the equation 3x^2-19x+20=0 are x=5,x= 4/3

Find the zeros of 3x^2-19x+20=0

The zeros of 3x^2-19x+20=0 are x=5,x= 4/3

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3 x^{2} - 19 x + 20 = 0

x = 5, x = \frac{4}{3}

Decimal Notation

x = 5, x = 1.33333 \dots

Solution steps

3 x^{2} - 19 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 3 \cdot 20}{2 \cdot 3}

(- 19)^{2} - 4 \cdot 3 \cdot 20 = 11

x_{1, 2} = \frac{- ( - 19 ) \pm 11}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 11}{2 \cdot 3}, x_{2} = \frac{- ( - 19 ) - 11}{2 \cdot 3}

x = \frac{- ( - 19 ) + 11}{2 \cdot 3} : 5

x = \frac{- ( - 19 ) - 11}{2 \cdot 3} : \frac{4}{3}

The solutions to the quadratic equation are:

x = 5, x = \frac{4}{3}

- 3 \leq x + 2 \leq 8

2 (2 x - 1) > 4 x

∣ x - 10 ∣ < 1

(x + 7) (x - 3) = (x + 1)^{2}

24 3^{\frac{6}{5}}

What are the solutions to the equation 3x^2-19x+20=0 ?
The solutions to the equation 3x^2-19x+20=0 are x=5,x= 4/3
Find the zeros of 3x^2-19x+20=0
The zeros of 3x^2-19x+20=0 are x=5,x= 4/3