What are the solutions to the equation x^2-8x-16=0 ?

The solutions to the equation x^2-8x-16=0 are x=4(1+sqrt(2)),x=4(1-sqrt(2))

Find the zeros of x^2-8x-16=0

The zeros of x^2-8x-16=0 are x=4(1+sqrt(2)),x=4(1-sqrt(2))

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x^{2} - 8 x - 16 = 0

x = 4 (1 + 2), x = 4 (1 - 2)

Decimal Notation

x = 9.65685 \dots, x = - 1.65685 \dots

Solution steps

x^{2} - 8 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 16) = 82

x_{1, 2} = \frac{- ( - 8 ) \pm 8 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 8 2}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 8 2}{2 \cdot 1}

x = \frac{- ( - 8 ) + 8 2}{2 \cdot 1} : 4 (1 + 2)

x = \frac{- ( - 8 ) - 8 2}{2 \cdot 1} : 4 (1 - 2)

The solutions to the quadratic equation are:

x = 4 (1 + 2), x = 4 (1 - 2)

6 x^{2} + 6 x + 7 = 0

x^{3} \cdot x^{\frac{1}{2}}

1 - \frac{2}{x} > 3 x

\frac{2 + 3 i}{4 + i}

- 7 k \leq - 84

What are the solutions to the equation x^2-8x-16=0 ?
The solutions to the equation x^2-8x-16=0 are x=4(1+sqrt(2)),x=4(1-sqrt(2))
Find the zeros of x^2-8x-16=0
The zeros of x^2-8x-16=0 are x=4(1+sqrt(2)),x=4(1-sqrt(2))