What are the solutions to the equation 4x^2=36 ?

The solutions to the equation 4x^2=36 are x=3,x=-3

Find the zeros of 4x^2=36

The zeros of 4x^2=36 are x=3,x=-3

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4 x^{2} = 36

x = 3, x = - 3

Solution steps

4 x^{2} = 36

Divide both sides by

4

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

\frac{x}{x - 1} - \frac{2}{x + 1} < \frac{8}{x ^{2} - 1}

7 (x - 3) + (x - 1) (x + 1) = x^{(2)} - 5 (x + 2)

\frac{x}{3} < 2

3 \cdot \frac{5}{2}

\frac{1}{\frac{7}{25}}

What are the solutions to the equation 4x^2=36 ?
The solutions to the equation 4x^2=36 are x=3,x=-3
Find the zeros of 4x^2=36
The zeros of 4x^2=36 are x=3,x=-3