What is (3^{-4}*3^{-6})^4 ?

The solution to (3^{-4}*3^{-6})^4 is 1/(3^{24)*43046721}

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simplify (3^{-4}*3^{-6})^4

simplify

(3^{- 4} \cdot 3^{- 6})^{4}

\frac{1}{3 ^{24} \cdot 43046721}

Decimal Notation

8.22526 E - 20

Solution steps

(3^{- 4} \cdot 3^{- 6})^{4}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(3^{- 4} \cdot 3^{- 6})^{4} = (3^{- 4})^{4} (3^{- 6})^{4}

= (3^{- 4})^{4} (3^{- 6})^{4}

(3^{- 4})^{4} = \frac{1}{43046721}

= \frac{1}{43046721} (3^{- 6})^{4}

Apply exponent rule:

(a^{b})^{c} = a^{b c}, a \geq 0

(3^{- 6})^{4} = 3^{- 6 \cdot 4}

= \frac{1}{43046721} \cdot 3^{- 6 \cdot 4}

Multiply the numbers:

6 \cdot 4 = 24

= \frac{1}{43046721} \cdot 3^{- 24}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

3^{- 24} = \frac{1}{3 ^{24}}

= \frac{1}{43046721} \cdot \frac{1}{3 ^{24}}

\frac{1}{43046721} \cdot \frac{1}{3 ^{24}} = \frac{1}{3 ^{24} \cdot 43046721}

= \frac{1}{3 ^{24} \cdot 43046721}

x x^{9}

4 x + 16 x y + 9 y + 36 y^{2}

\frac{10}{2 2}

\frac{x ^{2} - 4}{2 x + 4}

(8 x - 4) (4 x^{2} - 3 x + 2)

What is (3^{-4}*3^{-6})^4 ?
The solution to (3^{-4}*3^{-6})^4 is 1/(3^{24)*43046721}