What are the solutions to the equation -x^2+20x=100 ?

The solutions to the equation -x^2+20x=100 are x=10

Find the zeros of -x^2+20x=100

The zeros of -x^2+20x=100 are x=10

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- x^{2} + 20 x = 100

x = 10

Solution steps

- x^{2} + 20 x = 100

Move

100

to the left side

- x^{2} + 20 x - 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 ( - 1 ) ( - 100 )}{2 ( - 1 )}

2 0^{2} - 4 (- 1) (- 100) = 0

x_{1, 2} = \frac{- 20 \pm 0}{2 ( - 1 )}

x = \frac{- 20}{2 ( - 1 )}

\frac{- 20}{2 ( - 1 )} = 10

x = 10

The solution to the quadratic equation is:

x = 10

5 = \frac{x + 5}{3}

∣ 3 - x ∣ < 5

10 - 23

- 1 (1.4 s - 6) = 2 s - 28

x^{2} + 0.5 x + 4 = 0

What are the solutions to the equation -x^2+20x=100 ?
The solutions to the equation -x^2+20x=100 are x=10
Find the zeros of -x^2+20x=100
The zeros of -x^2+20x=100 are x=10