What is ((2-i))/((3+i)) ?

The solution to ((2-i))/((3+i)) is 1/2-1/2 i

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simplify ((2-i))/((3+i))

simplify

\frac{( 2 - i )}{( 3 + i )}

\frac{1}{2} - \frac{1}{2} i

Solution steps

\frac{2 - i}{3 + i}

Multiply by the conjugate

\frac{3 - i}{3 - i}

= \frac{( 2 - i ) ( 3 - i )}{( 3 + i ) ( 3 - i )}

Simplify

\frac{( 2 - i ) ( 3 - i )}{( 3 + i ) ( 3 - i )} : \frac{5 - 5 i}{10}

= \frac{5 - 5 i}{10}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{5}{10} + \frac{- 5}{10} i

Simplify

\frac{5}{10} + \frac{- 5}{10} i : \frac{1}{2} - \frac{1}{2} i

= \frac{1}{2} - \frac{1}{2} i

(\frac{2 ^{- 4}}{2 ^{- 2}})^{- 1}

(x^{3} y) (- 5 x^{2})

\frac{9}{10} \div \frac{1}{2}

(4 x^{3} + 3 y^{5})^{3}

0.8 7^{2}