What are the solutions to the equation 3b^2+6b+91=10 ?

The solutions to the equation 3b^2+6b+91=10 are b=-1+sqrt(26)i,b=-1-sqrt(26)i

Find the zeros of 3b^2+6b+91=10

The zeros of 3b^2+6b+91=10 are b=-1+sqrt(26)i,b=-1-sqrt(26)i

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3 b^{2} + 6 b + 91 = 10

b = - 1 + 26 i, b = - 1 - 26 i

Solution steps

3 b^{2} + 6 b + 91 = 10

Move

10

to the left side

3 b^{2} + 6 b + 81 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 \cdot 81}{2 \cdot 3}

Simplify

6^{2} - 4 \cdot 3 \cdot 81 : 626 i

b_{1, 2} = \frac{- 6 \pm 6 26 i}{2 \cdot 3}

Separate the solutions

b_{1} = \frac{- 6 + 6 26 i}{2 \cdot 3}, b_{2} = \frac{- 6 - 6 26 i}{2 \cdot 3}

b = \frac{- 6 + 6 26 i}{2 \cdot 3} : - 1 + 26 i

b = \frac{- 6 - 6 26 i}{2 \cdot 3} : - 1 - 26 i

The solutions to the quadratic equation are:

b = - 1 + 26 i, b = - 1 - 26 i

\frac{y}{5} - \frac{1}{2} (\frac{y}{2}) = \frac{7}{20}

\frac{u - v}{8 v} + \frac{6 u - 3 v}{8 v}

x^{2} - 8 x - 180 = 0

\frac{x}{2} + \frac{1}{4} > - \frac{1}{4} - \frac{x}{2}

\frac{360}{180} \frac{100000 - 95700}{100000}

What are the solutions to the equation 3b^2+6b+91=10 ?
The solutions to the equation 3b^2+6b+91=10 are b=-1+sqrt(26)i,b=-1-sqrt(26)i
Find the zeros of 3b^2+6b+91=10
The zeros of 3b^2+6b+91=10 are b=-1+sqrt(26)i,b=-1-sqrt(26)i