What is expand (2x^2-3x+2)(x+4) ?

The solution to expand (2x^2-3x+2)(x+4) is 2x^3+5x^2-10x+8

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expand (2x^2-3x+2)(x+4)

expand

(2 x^{2} - 3 x + 2) (x + 4)

2 x^{3} + 5 x^{2} - 10 x + 8

Solution steps

(2 x^{2} - 3 x + 2) (x + 4)

Distribute parentheses

= 2 x^{2} x + 2 x^{2} \cdot 4 - 3 xx - 3 x \cdot 4 + 2 x + 2 \cdot 4

Simplify

2 x^{2} x + 2 x^{2} \cdot 4 - 3 xx - 3 x \cdot 4 + 2 x + 2 \cdot 4 : 2 x^{3} + 5 x^{2} - 10 x + 8

= 2 x^{3} + 5 x^{2} - 10 x + 8

\frac{n ^{2} - 9}{n ^{2} - 6 n + 9}

1 + (- \frac{3}{2})

(\frac{a}{2})^{2}

\frac{63}{90}

6 w^{2} + 11 w + 8 w^{2} - 15 w

What is expand (2x^2-3x+2)(x+4) ?
The solution to expand (2x^2-3x+2)(x+4) is 2x^3+5x^2-10x+8