What are the solutions to the equation s^2+4s-5=0 ?

The solutions to the equation s^2+4s-5=0 are s=1,s=-5

Find the zeros of s^2+4s-5=0

The zeros of s^2+4s-5=0 are s=1,s=-5

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s^{2} + 4 s - 5 = 0

s = 1, s = - 5

Solution steps

s^{2} + 4 s - 5 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 5) = 6

s_{1, 2} = \frac{- 4 \pm 6}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 4 + 6}{2 \cdot 1}, s_{2} = \frac{- 4 - 6}{2 \cdot 1}

s = \frac{- 4 + 6}{2 \cdot 1} : 1

s = \frac{- 4 - 6}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

s = 1, s = - 5

(3 x + 2)^{2}

(3 x)^{- 3}

(z + 4)^{2} = - 9

\frac{3 d + 2 d - 3}{4} > 18

20 0^{\frac{1}{3}}

What are the solutions to the equation s^2+4s-5=0 ?
The solutions to the equation s^2+4s-5=0 are s=1,s=-5
Find the zeros of s^2+4s-5=0
The zeros of s^2+4s-5=0 are s=1,s=-5