What are the solutions to the equation (z+4)^2=-9 ?

The solutions to the equation (z+4)^2=-9 are z=3i-4,z=-3i-4

Find the zeros of (z+4)^2=-9

The zeros of (z+4)^2=-9 are z=3i-4,z=-3i-4

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(z + 4)^{2} = - 9

z = 3 i - 4, z = - 3 i - 4

Solution steps

(z + 4)^{2} = - 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + 4 = - 9 : z = 3 i - 4

Solve

z + 4 = - - 9 : z = - 3 i - 4

The solutions to the quadratic equation are:

z = 3 i - 4, z = - 3 i - 4

\frac{3 d + 2 d - 3}{4} > 18

20 0^{\frac{1}{3}}

3 ∣ 5 + x ∣ - 1 \geq 23

2 (x - 2)^{2} + 8 (x - 2) - 1 = 0

5 x - 6 = 2 x

What are the solutions to the equation (z+4)^2=-9 ?
The solutions to the equation (z+4)^2=-9 are z=3i-4,z=-3i-4
Find the zeros of (z+4)^2=-9
The zeros of (z+4)^2=-9 are z=3i-4,z=-3i-4