What are the solutions to the equation 4x^2+21=20x ?

The solutions to the equation 4x^2+21=20x are x= 7/2 ,x= 3/2

Find the zeros of 4x^2+21=20x

The zeros of 4x^2+21=20x are x= 7/2 ,x= 3/2

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4 x^{2} + 21 = 20 x

x = \frac{7}{2}, x = \frac{3}{2}

Solution steps

4 x^{2} + 21 = 20 x

Move

20 x

to the left side

4 x^{2} + 21 - 20 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 20 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 21}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 21 = 8

x_{1, 2} = \frac{- ( - 20 ) \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 8}{2 \cdot 4}, x_{2} = \frac{- ( - 20 ) - 8}{2 \cdot 4}

x = \frac{- ( - 20 ) + 8}{2 \cdot 4} : \frac{7}{2}

x = \frac{- ( - 20 ) - 8}{2 \cdot 4} : \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = \frac{3}{2}

2 - x^{2} = 10 - 6 x

x^{2} + 2 x - 8 = - 8

- \frac{7}{8} > - 0.5

6 m^{3} - 12 mn + m^{2} n - 2 n^{2}

- 4 x^{2} + 7 x - 3 = 0

What are the solutions to the equation 4x^2+21=20x ?
The solutions to the equation 4x^2+21=20x are x= 7/2 ,x= 3/2
Find the zeros of 4x^2+21=20x
The zeros of 4x^2+21=20x are x= 7/2 ,x= 3/2