What are the solutions to the equation -4x^2+7x-3=0 ?

The solutions to the equation -4x^2+7x-3=0 are x= 3/4 ,x=1

Find the zeros of -4x^2+7x-3=0

The zeros of -4x^2+7x-3=0 are x= 3/4 ,x=1

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- 4 x^{2} + 7 x - 3 = 0

x = \frac{3}{4}, x = 1

Solution steps

- 4 x^{2} + 7 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 4 ) ( - 3 )}{2 ( - 4 )}

7^{2} - 4 (- 4) (- 3) = 1

x_{1, 2} = \frac{- 7 \pm 1}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 7 + 1}{2 ( - 4 )}, x_{2} = \frac{- 7 - 1}{2 ( - 4 )}

x = \frac{- 7 + 1}{2 ( - 4 )} : \frac{3}{4}

x = \frac{- 7 - 1}{2 ( - 4 )} : 1

The solutions to the quadratic equation are:

x = \frac{3}{4}, x = 1

\frac{2}{\frac{2}{3}}

3 v^{2} + 10 v + 3

\frac{1}{3 + 1} + \frac{1}{3 - 1}

3 c^{2} + 10 c + 8

x^{2} - 13 x + 15 = 0

What are the solutions to the equation -4x^2+7x-3=0 ?
The solutions to the equation -4x^2+7x-3=0 are x= 3/4 ,x=1
Find the zeros of -4x^2+7x-3=0
The zeros of -4x^2+7x-3=0 are x= 3/4 ,x=1