What are the solutions to the equation x^2+10x=-24 ?

The solutions to the equation x^2+10x=-24 are x=-4,x=-6

Find the zeros of x^2+10x=-24

The zeros of x^2+10x=-24 are x=-4,x=-6

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x^{2} + 10 x = - 24

x = - 4, x = - 6

Solution steps

x^{2} + 10 x = - 24

Move

24

to the left side

x^{2} + 10 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 24 = 2

x_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2}{2 \cdot 1}, x_{2} = \frac{- 10 - 2}{2 \cdot 1}

x = \frac{- 10 + 2}{2 \cdot 1} : - 4

x = \frac{- 10 - 2}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = - 4, x = - 6

4 (x - 7) + 4 = 36

\frac{6}{6}

0 = x^{2} + 8 x + 16

x + 3 = 0

m - 4 > 12

What are the solutions to the equation x^2+10x=-24 ?
The solutions to the equation x^2+10x=-24 are x=-4,x=-6
Find the zeros of x^2+10x=-24
The zeros of x^2+10x=-24 are x=-4,x=-6