What is factor am^2+bm^2+an^2+bn^2 ?

The solution to factor am^2+bm^2+an^2+bn^2 is (m^2+n^2)(a+b)

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factor am^2+bm^2+an^2+bn^2

factor

a m^{2} + b m^{2} + a n^{2} + b n^{2}

(m^{2} + n^{2}) (a + b)

Solution steps

a m^{2} + b m^{2} + a n^{2} + b n^{2}

Factor out common term

a

= a (m^{2} + n^{2}) + b m^{2} + b n^{2}

Factor out common term

b

= a (m^{2} + n^{2}) + b (m^{2} + n^{2})

Factor out common term

(m^{2} + n^{2})

= (m^{2} + n^{2}) (a + b)

\frac{x - 1}{x - 1}

4^{2} - 9

- cos (9 α + 6 θ) sin (9 α + 6 θ)

+ 2 (p - q)^{2} - (p - q) - 1

3 x + (- 2)

What is factor am^2+bm^2+an^2+bn^2 ?
The solution to factor am^2+bm^2+an^2+bn^2 is (m^2+n^2)(a+b)