What are the solutions to the equation -2x^2+24=8x ?

The solutions to the equation -2x^2+24=8x are x=-6,x=2

Find the zeros of -2x^2+24=8x

The zeros of -2x^2+24=8x are x=-6,x=2

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- 2 x^{2} + 24 = 8 x

x = - 6, x = 2

Solution steps

- 2 x^{2} + 24 = 8 x

Move

8 x

to the left side

- 2 x^{2} + 24 - 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 x^{2} - 8 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 2 ) \cdot 24}{2 ( - 2 )}

(- 8)^{2} - 4 (- 2) \cdot 24 = 16

x_{1, 2} = \frac{- ( - 8 ) \pm 16}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 16}{2 ( - 2 )}, x_{2} = \frac{- ( - 8 ) - 16}{2 ( - 2 )}

x = \frac{- ( - 8 ) + 16}{2 ( - 2 )} : - 6

x = \frac{- ( - 8 ) - 16}{2 ( - 2 )} : 2

The solutions to the quadratic equation are:

x = - 6, x = 2

3 x^{2} + 2 x + 6 = 5

2 + x < 9 x + 6

2 (\frac{1}{3})^{2} + 5 (\frac{1}{3}) + 6

6 + 3 ∣ 2 x + 7 ∣ = 30

\frac{8}{9} + 1

What are the solutions to the equation -2x^2+24=8x ?
The solutions to the equation -2x^2+24=8x are x=-6,x=2
Find the zeros of -2x^2+24=8x
The zeros of -2x^2+24=8x are x=-6,x=2