What are the solutions to the equation 12x^2-12x+3=0 ?

The solutions to the equation 12x^2-12x+3=0 are x= 1/2

Find the zeros of 12x^2-12x+3=0

The zeros of 12x^2-12x+3=0 are x= 1/2

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12 x^{2} - 12 x + 3 = 0

x = \frac{1}{2}

Solution steps

12 x^{2} - 12 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 12 \cdot 3}{2 \cdot 12}

(- 12)^{2} - 4 \cdot 12 \cdot 3 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 12}

x = \frac{- ( - 12 )}{2 \cdot 12}

\frac{- ( - 12 )}{2 \cdot 12} = \frac{1}{2}

x = \frac{1}{2}

The solution to the quadratic equation is:

x = \frac{1}{2}

\frac{4 x + 8}{x - 5} < 0

3 x^{2} + 8 x + 1 = 0

\frac{v}{5} - 6 = 3

x^{3} - x^{2} - 7 x + 7

(- 9) (- 9)^{3}

What are the solutions to the equation 12x^2-12x+3=0 ?
The solutions to the equation 12x^2-12x+3=0 are x= 1/2
Find the zeros of 12x^2-12x+3=0
The zeros of 12x^2-12x+3=0 are x= 1/2