What is factor 125z^{18}-8k^{12}m^6 ?

The solution to factor 125z^{18}-8k^{12}m^6 is (5z^6-2k^4m^2)(25z^{12}+10k^4z^6m^2+4k^8m^4)

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factor 125z^{18}-8k^{12}m^6

factor

125 z^{18} - 8 k^{12} m^{6}

(5 z^{6} - 2 k^{4} m^{2}) (25 z^{12} + 10 k^{4} z^{6} m^{2} + 4 k^{8} m^{4})

Solution steps

125 z^{18} - 8 k^{12} m^{6}

Rewrite

125 z^{18}

(5 z^{6})^{3}

Rewrite

8 k^{12} m^{6}

(2 k^{4} m^{2})^{3}

= (5 z^{6})^{3} - (2 k^{4} m^{2})^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(5 z^{6})^{3} - (2 k^{4} m^{2})^{3} = (5 z^{6} - 2 k^{4} m^{2}) ((5 z^{6})^{2} + 5 z^{6} 2 k^{4} m^{2} + (2 k^{4} m^{2})^{2})

= (5 z^{6} - 2 k^{4} m^{2}) ((5 z^{6})^{2} + 5 z^{6} 2 k^{4} m^{2} + (2 k^{4} m^{2})^{2})

Simplify

(5 z^{6} - 2 k^{4} m^{2}) ((5 z^{6})^{2} + 5 z^{6} \cdot 2 k^{4} m^{2} + (2 k^{4} m^{2})^{2}) : (5 z^{6} - 2 k^{4} m^{2}) (25 z^{12} + 10 k^{4} z^{6} m^{2} + 4 k^{8} m^{4})

= (5 z^{6} - 2 k^{4} m^{2}) (25 z^{12} + 10 k^{4} z^{6} m^{2} + 4 k^{8} m^{4})

1 - 0.09 a^{2}

15 d^{2} e^{4} - 10 d^{3} e^{6} f

6 a c - 2 b d + 4 b c - 3 a d

lo g_{10} (a^{2} - b^{2})

(a \cdot b) \cdot (c \cdot d)

What is factor 125z^{18}-8k^{12}m^6 ?
The solution to factor 125z^{18}-8k^{12}m^6 is (5z^6-2k^4m^2)(25z^{12}+10k^4z^6m^2+4k^8m^4)