What are the solutions to the equation 3.5=-16t^2+16t ?

The solutions to the equation 3.5=-16t^2+16t are t=(4-sqrt(2))/8 ,t=(4+sqrt(2))/8

Find the zeros of 3.5=-16t^2+16t

The zeros of 3.5=-16t^2+16t are t=(4-sqrt(2))/8 ,t=(4+sqrt(2))/8

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3.5 = - 16 t^{2} + 16 t

t = \frac{4 - 2}{8}, t = \frac{4 + 2}{8}

Decimal Notation

t = 0.32322 \dots, t = 0.67677 \dots

Solution steps

3.5 = - 16 t^{2} + 16 t

Multiply both sides by

10

35 = - 160 t^{2} + 160 t

Switch sides

- 160 t^{2} + 160 t = 35

Move

35

to the left side

- 160 t^{2} + 160 t - 35 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 160 \pm 16 0 ^{2} - 4 ( - 160 ) ( - 35 )}{2 ( - 160 )}

16 0^{2} - 4 (- 160) (- 35) = 402

t_{1, 2} = \frac{- 160 \pm 40 2}{2 ( - 160 )}

Separate the solutions

t_{1} = \frac{- 160 + 40 2}{2 ( - 160 )}, t_{2} = \frac{- 160 - 40 2}{2 ( - 160 )}

t = \frac{- 160 + 40 2}{2 ( - 160 )} : \frac{4 - 2}{8}

t = \frac{- 160 - 40 2}{2 ( - 160 )} : \frac{4 + 2}{8}

The solutions to the quadratic equation are:

t = \frac{4 - 2}{8}, t = \frac{4 + 2}{8}

- \frac{1}{3} - \frac{1}{5}

- 8 x - 29 = 55 - 12 x

7 x^{2} + 15 x + 2

6 + 5 x - 3 x^{2} = 7

∣ d + 4 ∣ => 3

What are the solutions to the equation 3.5=-16t^2+16t ?
The solutions to the equation 3.5=-16t^2+16t are t=(4-sqrt(2))/8 ,t=(4+sqrt(2))/8
Find the zeros of 3.5=-16t^2+16t
The zeros of 3.5=-16t^2+16t are t=(4-sqrt(2))/8 ,t=(4+sqrt(2))/8