What are the solutions to the equation 5a^2-31a=28 ?

The solutions to the equation 5a^2-31a=28 are a=7,a=-4/5

Find the zeros of 5a^2-31a=28

The zeros of 5a^2-31a=28 are a=7,a=-4/5

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5 a^{2} - 31 a = 28

a = 7, a = - \frac{4}{5}

Solution steps

5 a^{2} - 31 a = 28

Move

28

to the left side

5 a^{2} - 31 a - 28 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 31 ) \pm ( - 31 ) ^{2} - 4 \cdot 5 ( - 28 )}{2 \cdot 5}

(- 31)^{2} - 4 \cdot 5 (- 28) = 39

a_{1, 2} = \frac{- ( - 31 ) \pm 39}{2 \cdot 5}

Separate the solutions

a_{1} = \frac{- ( - 31 ) + 39}{2 \cdot 5}, a_{2} = \frac{- ( - 31 ) - 39}{2 \cdot 5}

a = \frac{- ( - 31 ) + 39}{2 \cdot 5} : 7

a = \frac{- ( - 31 ) - 39}{2 \cdot 5} : - \frac{4}{5}

The solutions to the quadratic equation are:

a = 7, a = - \frac{4}{5}

∣ x - 6 ∣ = 26

x^{2} - 4 x - 9 = 0

\frac{1}{3}

ab + a^{2}

5 \cdot X^{0} + 3 \cdot X^{1} + 3 \cdot X^{2} = 1 \cdot X^{0} + 0 \cdot X^{1}

What are the solutions to the equation 5a^2-31a=28 ?
The solutions to the equation 5a^2-31a=28 are a=7,a=-4/5
Find the zeros of 5a^2-31a=28
The zeros of 5a^2-31a=28 are a=7,a=-4/5