What is factor (e^8-1)/(40) ?

The solution to factor (e^8-1)/(40) is ((e^4+1)(e^2+1)(e+1)(e-1))/(40)

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factor (e^8-1)/(40)

factor

\frac{e ^{8} - 1}{40}

\frac{( e ^{4} + 1 ) ( e ^{2} + 1 ) ( e + 1 ) ( e - 1 )}{40}

Solution steps

\frac{e ^{8} - 1}{40}

Factor

e^{8} - 1 : (e^{4} + 1) (e^{2} + 1) (e + 1) (e - 1)

= \frac{( e ^{4} + 1 ) ( e ^{2} + 1 ) ( e + 1 ) ( e - 1 )}{40}

cos (180 - 2 a)

x y - x z + 3 y - 3 z

(x - 5) + (4 x^{2})

9 b^{2 x} - \frac{1}{4}

e^{2 + 2 i}

What is factor (e^8-1)/(40) ?
The solution to factor (e^8-1)/(40) is ((e^4+1)(e^2+1)(e+1)(e-1))/(40)