What are the solutions to the equation 6v^2-12v=0 ?

The solutions to the equation 6v^2-12v=0 are v=2,v=0

Find the zeros of 6v^2-12v=0

The zeros of 6v^2-12v=0 are v=2,v=0

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6 v^{2} - 12 v = 0

v = 2, v = 0

Solution steps

6 v^{2} - 12 v = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 6 \cdot 0}{2 \cdot 6}

(- 12)^{2} - 4 \cdot 6 \cdot 0 = 12

v_{1, 2} = \frac{- ( - 12 ) \pm 12}{2 \cdot 6}

Separate the solutions

v_{1} = \frac{- ( - 12 ) + 12}{2 \cdot 6}, v_{2} = \frac{- ( - 12 ) - 12}{2 \cdot 6}

v = \frac{- ( - 12 ) + 12}{2 \cdot 6} : 2

v = \frac{- ( - 12 ) - 12}{2 \cdot 6} : 0

The solutions to the quadratic equation are:

v = 2, v = 0

x^{2} + 8 x + 17 = 0

5 x^{2} + 9 x - 6 = 0

(z + 8)^{2} = - 81

- 24 x - 15 = - 27

x - 1 < 6

What are the solutions to the equation 6v^2-12v=0 ?
The solutions to the equation 6v^2-12v=0 are v=2,v=0
Find the zeros of 6v^2-12v=0
The zeros of 6v^2-12v=0 are v=2,v=0