What are the solutions to the equation 5x^2+9x-6=0 ?

The solutions to the equation 5x^2+9x-6=0 are x=(-9+sqrt(201))/(10),x=(-9-sqrt(201))/(10)

Find the zeros of 5x^2+9x-6=0

The zeros of 5x^2+9x-6=0 are x=(-9+sqrt(201))/(10),x=(-9-sqrt(201))/(10)

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5 x^{2} + 9 x - 6 = 0

x = \frac{- 9 + 201}{10}, x = \frac{- 9 - 201}{10}

Solution steps

5 x^{2} + 9 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 5 ( - 6 )}{2 \cdot 5}

9^{2} - 4 \cdot 5 (- 6) = 201

x_{1, 2} = \frac{- 9 \pm 201}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 9 + 201}{2 \cdot 5}, x_{2} = \frac{- 9 - 201}{2 \cdot 5}

x = \frac{- 9 + 201}{2 \cdot 5} : \frac{- 9 + 201}{10}

x = \frac{- 9 - 201}{2 \cdot 5} : \frac{- 9 - 201}{10}

The solutions to the quadratic equation are:

x = \frac{- 9 + 201}{10}, x = \frac{- 9 - 201}{10}

(z + 8)^{2} = - 81

- 24 x - 15 = - 27

x - 1 < 6

243 x^{5} + 1

x^{2} - 6 x = 14

What are the solutions to the equation 5x^2+9x-6=0 ?
The solutions to the equation 5x^2+9x-6=0 are x=(-9+sqrt(201))/(10),x=(-9-sqrt(201))/(10)
Find the zeros of 5x^2+9x-6=0
The zeros of 5x^2+9x-6=0 are x=(-9+sqrt(201))/(10),x=(-9-sqrt(201))/(10)