What is factor a^2b^4c^6-d^8e^{10} ?

The solution to factor a^2b^4c^6-d^8e^{10} is (ab^2c^3+e^5d^4)(ab^2c^3-e^5d^4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor a^2b^4c^6-d^8e^{10}

factor

a^{2} b^{4} c^{6} - d^{8} e^{10}

(a b^{2} c^{3} + e^{5} d^{4}) (a b^{2} c^{3} - e^{5} d^{4})

Solution steps

a^{2} b^{4} c^{6} - d^{8} e^{10}

Rewrite

a^{2} b^{4} c^{6}

(a b^{2} c^{3})^{2}

Rewrite

d^{8} e^{10}

(d^{4} e^{5})^{2}

= (a b^{2} c^{3})^{2} - (d^{4} e^{5})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(a b^{2} c^{3})^{2} - (d^{4} e^{5})^{2} = (a b^{2} c^{3} + d^{4} e^{5}) (a b^{2} c^{3} - d^{4} e^{5})

= (a b^{2} c^{3} + d^{4} e^{5}) (a b^{2} c^{3} - d^{4} e^{5})

a x - 2 b x - 2 a y + 4 a y

2 cos^{2} (w) + 3 cos (w) - 5

[(6 a + b) + 4]^{2}

- (\frac{3}{2})

64 (o + p)^{3} - q^{3}

What is factor a^2b^4c^6-d^8e^{10} ?
The solution to factor a^2b^4c^6-d^8e^{10} is (ab^2c^3+e^5d^4)(ab^2c^3-e^5d^4)