What are the solutions to the equation z^2+z-20=0 ?

The solutions to the equation z^2+z-20=0 are z=4,z=-5

Find the zeros of z^2+z-20=0

The zeros of z^2+z-20=0 are z=4,z=-5

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z^{2} + z - 20 = 0

z = 4, z = - 5

Solution steps

z^{2} + z - 20 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 20) = 9

z_{1, 2} = \frac{- 1 \pm 9}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 1 + 9}{2 \cdot 1}, z_{2} = \frac{- 1 - 9}{2 \cdot 1}

z = \frac{- 1 + 9}{2 \cdot 1} : 4

z = \frac{- 1 - 9}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

z = 4, z = - 5

7 n - 21 > 21

3 x^{2} - 16 x - 12 = 0

\frac{- 16}{- 4}

- ∣ b + 4 ∣ + 1 = 10

6 x^{2} - 4 = 5 x

What are the solutions to the equation z^2+z-20=0 ?
The solutions to the equation z^2+z-20=0 are z=4,z=-5
Find the zeros of z^2+z-20=0
The zeros of z^2+z-20=0 are z=4,z=-5