What are the solutions to the equation 2x^2+6x-11=0 ?

The solutions to the equation 2x^2+6x-11=0 are x=(-3+sqrt(31))/2 ,x=-(3+sqrt(31))/2

Find the zeros of 2x^2+6x-11=0

The zeros of 2x^2+6x-11=0 are x=(-3+sqrt(31))/2 ,x=-(3+sqrt(31))/2

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2 x^{2} + 6 x - 11 = 0

x = \frac{- 3 + 31}{2}, x = - \frac{3 + 31}{2}

Decimal Notation

x = 1.28388 \dots, x = - 4.28388 \dots

Solution steps

2 x^{2} + 6 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 ( - 11 )}{2 \cdot 2}

6^{2} - 4 \cdot 2 (- 11) = 231

x_{1, 2} = \frac{- 6 \pm 2 31}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 6 + 2 31}{2 \cdot 2}, x_{2} = \frac{- 6 - 2 31}{2 \cdot 2}

x = \frac{- 6 + 2 31}{2 \cdot 2} : \frac{- 3 + 31}{2}

x = \frac{- 6 - 2 31}{2 \cdot 2} : - \frac{3 + 31}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 31}{2}, x = - \frac{3 + 31}{2}

\frac{a}{3 b} - 2 (\frac{a}{b} - \frac{b}{2 a})

∣ x - 1 ∣ + ∣ x - 2 ∣ > 1

b^{2} + b - 20

8^{3} = 16

x^{4} + 20 x^{2} + 100

What are the solutions to the equation 2x^2+6x-11=0 ?
The solutions to the equation 2x^2+6x-11=0 are x=(-3+sqrt(31))/2 ,x=-(3+sqrt(31))/2
Find the zeros of 2x^2+6x-11=0
The zeros of 2x^2+6x-11=0 are x=(-3+sqrt(31))/2 ,x=-(3+sqrt(31))/2