What are the solutions to the equation 100x^3+25x^2+4x+1=0 ?

The solutions to the equation 100x^3+25x^2+4x+1=0 are x=-1/4 ,x= 1/5 i,x=-1/5 i

Find the zeros of 100x^3+25x^2+4x+1=0

The zeros of 100x^3+25x^2+4x+1=0 are x=-1/4 ,x= 1/5 i,x=-1/5 i

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100 x^{3} + 25 x^{2} + 4 x + 1 = 0

x = - \frac{1}{4}, x = \frac{1}{5} i, x = - \frac{1}{5} i

Solution steps

100 x^{3} + 25 x^{2} + 4 x + 1 = 0

Factor

100 x^{3} + 25 x^{2} + 4 x + 1 : (4 x + 1) (25 x^{2} + 1)

(4 x + 1) (25 x^{2} + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x + 1 = 0 or 25 x^{2} + 1 = 0

Solve

4 x + 1 = 0 : x = - \frac{1}{4}

Solve

25 x^{2} + 1 = 0 : x = \frac{1}{5} i, x = - \frac{1}{5} i

The solutions are

x = - \frac{1}{4}, x = \frac{1}{5} i, x = - \frac{1}{5} i

\frac{n}{5} \leq 2

2 x^{2} + 7 = 4 x

\frac{2 q ^{- 9} b}{5 ( q ^{- 5} b ^{- 4} ) ^{2}}

(\frac{z}{5})^{2}

\frac{7}{12} - \frac{4}{9}

What are the solutions to the equation 100x^3+25x^2+4x+1=0 ?
The solutions to the equation 100x^3+25x^2+4x+1=0 are x=-1/4 ,x= 1/5 i,x=-1/5 i
Find the zeros of 100x^3+25x^2+4x+1=0
The zeros of 100x^3+25x^2+4x+1=0 are x=-1/4 ,x= 1/5 i,x=-1/5 i