What is (2q^{-9}b)/(5(q^{-5)b^{-4})^2} ?

The solution to (2q^{-9}b)/(5(q^{-5)b^{-4})^2} is (2qb^9)/5

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simplify (2q^{-9}b)/(5(q^{-5)b^{-4})^2}

simplify

\frac{2 q ^{- 9} b}{5 ( q ^{- 5} b ^{- 4} ) ^{2}}

\frac{2 q b ^{9}}{5}

Solution steps

\frac{2 q ^{- 9} b}{5 ( q ^{- 5} b ^{- 4} ) ^{2}}

Simplify

2 q^{- 9} b : \frac{2 b}{q ^{9}}

= \frac{\frac{2 b}{q ^{9}}}{5 ( q ^{- 5} b ^{- 4} ) ^{2}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{2 b}{q ^{9} \cdot 5 ( q ^{- 5} b ^{- 4} ) ^{2}}

Simplify

q^{9} \cdot 5 (q^{- 5} b^{- 4})^{2} : \frac{5}{q b ^{8}}

= \frac{2 b}{\frac{5}{q b ^{8}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{2 b q b ^{8}}{5}

Simplify

b b^{8} : b^{9}

= \frac{2 b ^{9} q}{5}

= \frac{2 q b ^{9}}{5}

(\frac{z}{5})^{2}

\frac{7}{12} - \frac{4}{9}

∣ x + 4 ∣ = 7.5

(\frac{a ^{- 3}}{b ^{2}})^{4}

\frac{2 - i}{i}

What is (2q^{-9}b)/(5(q^{-5)b^{-4})^2} ?
The solution to (2q^{-9}b)/(5(q^{-5)b^{-4})^2} is (2qb^9)/5