What is ((a^{-3})/(b^2))^4 ?

The solution to ((a^{-3})/(b^2))^4 is 1/(a^{12)b^8}

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simplify ((a^{-3})/(b^2))^4

simplify

(\frac{a ^{- 3}}{b ^{2}})^{4}

\frac{1}{a ^{12} b ^{8}}

Solution steps

(\frac{a ^{- 3}}{b ^{2}})^{4}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( a ^{- 3} ) ^{4}}{( b ^{2} ) ^{4}}

Simplify

(a^{- 3})^{4} : \frac{1}{a ^{12}}

= \frac{\frac{1}{a ^{12}}}{( b ^{2} ) ^{4}}

Simplify

(b^{2})^{4} : b^{8}

= \frac{\frac{1}{a ^{12}}}{b ^{8}}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{1}{a ^{12} b ^{8}}

\frac{2 - i}{i}

x \leq - 6 and x \geq - 5

- 9 x^{2} + 18 x = 14

a^{2} b + a^{4} b^{2}

(\frac{4}{5})^{4}

What is ((a^{-3})/(b^2))^4 ?
The solution to ((a^{-3})/(b^2))^4 is 1/(a^{12)b^8}