What is factor 2sin^2(θ)+5sin(θ)-3 ?

The solution to factor 2sin^2(θ)+5sin(θ)-3 is (2sin(θ)-1)(sin(θ)+3)

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factor 2sin^2(θ)+5sin(θ)-3

factor

2 sin^{2} (θ) + 5 sin (θ) - 3

(2 sin (θ) - 1) (sin (θ) + 3)

Solution steps

2 sin^{2} (θ) + 5 sin (θ) - 3

Break the expression into groups

= (2 sin^{2} (θ) - sin (θ)) + (6 sin (θ) - 3)

Factor out

sin (θ)

from

2 sin^{2} (θ) - sin (θ) : sin (θ) (2 sin (θ) - 1)

Factor out

3

from

6 sin (θ) - 3 : 3 (2 sin (θ) - 1)

= sin (θ) (2 sin (θ) - 1) + 3 (2 sin (θ) - 1)

Factor out common term

2 sin (θ) - 1

= (2 sin (θ) - 1) (sin (θ) + 3)

[- 2.7]

2 y^{- 1} + 11 y^{- 4}

2 (a + b)^{2} + 3 (a + b) - 2

(a \cdot b) + (a \cdot c)

49 m 6 - 70 am 3 n 2 + 25 a 2 n 4

What is factor 2sin^2(θ)+5sin(θ)-3 ?
The solution to factor 2sin^2(θ)+5sin(θ)-3 is (2sin(θ)-1)(sin(θ)+3)