What is factor (y+z)^3+64 ?

The solution to factor (y+z)^3+64 is (y+z+4)((y+z)^2-4(y+z)+16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor (y+z)^3+64

factor

(y + z)^{3} + 64

(y + z + 4) ((y + z)^{2} - 4 (y + z) + 16)

Solution steps

(y + z)^{3} + 64

Rewrite

64

4^{3}

= (y + z)^{3} + 4^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(y + z)^{3} + 4^{3} = ((y + z) + 4) ((y + z)^{2} - 4 (y + z) + 4^{2})

= ((y + z) + 4) ((y + z)^{2} - 4 (y + z) + 4^{2})

Refine

= (y + z + 4) ((y + z)^{2} - 4 (y + z) + 16)

Z Y + X Y - X - Z

(x + 1)^{2} - (x + 1) - 6

a x^{3} + b x^{2} + a x + b

x^{10} + 9 x^{5} + 8

x^{2} + 3 x - 28 x^{2} + 3 x - 28

What is factor (y+z)^3+64 ?
The solution to factor (y+z)^3+64 is (y+z+4)((y+z)^2-4(y+z)+16)