What is factor (4x-3)^3-8 ?

The solution to factor (4x-3)^3-8 is (4x-5)(16x^2-16x+7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor (4x-3)^3-8

factor

(4 x - 3)^{3} - 8

(4 x - 5) (16 x^{2} - 16 x + 7)

Solution steps

(4 x - 3)^{3} - 8

Rewrite

8

2^{3}

= (4 x - 3)^{3} - 2^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(4 x - 3)^{3} - 2^{3} = ((4 x - 3) - 2) ((4 x - 3)^{2} + 2 (4 x - 3) + 2^{2})

= ((4 x - 3) - 2) ((4 x - 3)^{2} + 2 (4 x - 3) + 2^{2})

Refine

= (4 x - 5) ((4 x - 3)^{2} + 2 (4 x - 3) + 4)

Expand

(4 x - 3)^{2} + 2 (4 x - 3) + 4 : 16 x^{2} - 16 x + 7

= (4 x - 5) (16 x^{2} - 16 x + 7)

(x + 1) - 2 y

\frac{1}{2} x^{2} + x - 12

a x + ab + 2 y x + 2 y b

4 q a + 5 q^{2} + 4 d a + 5 d q

a (c t - \frac{b}{a} x)

What is factor (4x-3)^3-8 ?
The solution to factor (4x-3)^3-8 is (4x-5)(16x^2-16x+7)