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Popular >

7-|2x+8|<= 3

Solution

7 - ∣ 2 x + 8 ∣ \leq 3

Solution

x \leq - 6 or x \geq - 2

+1

Interval Notation

(- \infty, - 6] \cup [- 2, \infty)

Solution steps

7 - ∣ 2 x + 8 ∣ \leq 3

Move

7

to the right side

- ∣ 2 x + 8 ∣ \leq - 4

Multiply both sides by

- 1

∣ 2 x + 8 ∣ \geq 4

Apply absolute rule: If

∣ u ∣ \geq a, a > 0

then

u \leq - a

or

u \geq a

2 x + 8 \leq - 4 or 2 x + 8 \geq 4

2 x + 8 \leq - 4 or 2 x + 8 \geq 4

x \leq - 6 or x \geq - 2

Popular Examples

simplify sqrt(5^2+8^2)simplify

5^{2} + 8^{2}

3 x^{2} - 8 = 0

simplify 3^0 simplify

3^{0}

5 x - 4 = 21

(4e^{2(2^3)})/(12x^2)<= 0.001

\frac{4 e ^{2 (2^{3})}}{12 x ^{2}} \leq 0.001

Frequently Asked Questions (FAQ)

What is 7-|2x+8|<= 3 ?
The solution to 7-|2x+8|<= 3 is x<=-6\lor x>=-2