What is factor Ae^{4x}+Bxe^{4x} ?

The solution to factor Ae^{4x}+Bxe^{4x} is e^{4x}(A+Bx)

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factor Ae^{4x}+Bxe^{4x}

factor

A e^{4 x} + B x e^{4 x}

e^{4 x} (A + B x)

Solution steps

A e^{4 x} + B x e^{4 x}

Factor out common term

e^{4 x}

= e^{4 x} (A + B x)

2^{2} - x - 2

(x + y)^{2} - 9 (x + y) + 20

(A + B t^{1}) (A + B t^{2})

f (x) - e^{2 x}

(y + 1)^{3} - 27 y^{3}

What is factor Ae^{4x}+Bxe^{4x} ?
The solution to factor Ae^{4x}+Bxe^{4x} is e^{4x}(A+Bx)