What is factor 5+(2x+3)2-(3x+2)(x+1) ?

The solution to factor 5+(2x+3)2-(3x+2)(x+1) is -3(x-(sqrt(109)-1)/6)(x-(-1-sqrt(109))/6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 5+(2x+3)2-(3x+2)(x+1)

factor

5 + (2 x + 3) 2 - (3 x + 2) (x + 1)

- 3 (x - \frac{109 - 1}{6}) (x - \frac{- 1 - 109}{6})

Solution steps

5 + (2 x + 3) \cdot 2 - (3 x + 2) (x + 1)

Expand

5 + (2 x + 3) \cdot 2 - (3 x + 2) (x + 1) : - 3 x^{2} - x + 9

= - 3 x^{2} - x + 9

Factor

- 3 x^{2} - x + 9 : - 3 (x - \frac{- 1 + 109}{6}) (x - \frac{- 1 - 109}{6})

= - 3 (x - \frac{109 - 1}{6}) (x - \frac{- 1 - 109}{6})

(4 x^{2})^{2} - 8 (4 x^{2}) - 105

(cos (x + y))^{2}

m p + m q - 3 p - 3 q

ln (s) in x (sin (x))

a e^{4 x} - a e^{- 4 x}

What is factor 5+(2x+3)2-(3x+2)(x+1) ?
The solution to factor 5+(2x+3)2-(3x+2)(x+1) is -3(x-(sqrt(109)-1)/6)(x-(-1-sqrt(109))/6)