What is factor-cos(10a+2θ)sin(10a+2θ) ?

The solution to factor-cos(10a+2θ)sin(10a+2θ) is -cos(2(5a+θ))sin(2(5a+θ))

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factor-cos(10a+2θ)sin(10a+2θ)

factor

- cos (10 a + 2 θ) sin (10 a + 2 θ)

- cos (2 (5 a + θ)) sin (2 (5 a + θ))

Solution steps

- cos (10 a + 2 θ) sin (10 a + 2 θ)

Factor

10 a + 2 θ : 2 (5 a + θ)

= - sin (2 θ + 10 a) cos (2 (θ + 5 a))

Factor

10 a + 2 θ : 2 (5 a + θ)

= - cos (2 (θ + 5 a)) sin (2 (θ + 5 a))

(u \cdot v) \cdot (x \cdot b)

\frac{5}{1}

x^{2 x} + x^{x} - 12

x^{2} - \frac{62}{6}

(5 x + 1)^{2} + 16 (5 x + 1) + 64

What is factor-cos(10a+2θ)sin(10a+2θ) ?
The solution to factor-cos(10a+2θ)sin(10a+2θ) is -cos(2(5a+θ))sin(2(5a+θ))