What are the solutions to the equation 2x^2+9x-1=0 ?

The solutions to the equation 2x^2+9x-1=0 are x=(-9+sqrt(89))/4 ,x=(-9-sqrt(89))/4

Find the zeros of 2x^2+9x-1=0

The zeros of 2x^2+9x-1=0 are x=(-9+sqrt(89))/4 ,x=(-9-sqrt(89))/4

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2 x^{2} + 9 x - 1 = 0

x = \frac{- 9 + 89}{4}, x = \frac{- 9 - 89}{4}

Decimal Notation

x = 0.10849 \dots, x = - 4.60849 \dots

Solution steps

2 x^{2} + 9 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

9^{2} - 4 \cdot 2 (- 1) = 89

x_{1, 2} = \frac{- 9 \pm 89}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 9 + 89}{2 \cdot 2}, x_{2} = \frac{- 9 - 89}{2 \cdot 2}

x = \frac{- 9 + 89}{2 \cdot 2} : \frac{- 9 + 89}{4}

x = \frac{- 9 - 89}{2 \cdot 2} : \frac{- 9 - 89}{4}

The solutions to the quadratic equation are:

x = \frac{- 9 + 89}{4}, x = \frac{- 9 - 89}{4}

\frac{- 9 - 2 i}{- 8 - i}

e^{2 l n (7)}

h (- 2) = \frac{6 + ( - 2 ) ^{3}}{( - 2 ) ^{3}}

\frac{8 a ^{4} b ^{- 6}}{4 a ^{7} b ^{- 6}}

5 \cdot \frac{1}{2}

What are the solutions to the equation 2x^2+9x-1=0 ?
The solutions to the equation 2x^2+9x-1=0 are x=(-9+sqrt(89))/4 ,x=(-9-sqrt(89))/4
Find the zeros of 2x^2+9x-1=0
The zeros of 2x^2+9x-1=0 are x=(-9+sqrt(89))/4 ,x=(-9-sqrt(89))/4