What are the solutions to the equation -x^2=3x ?

The solutions to the equation -x^2=3x are x=-3,x=0

Find the zeros of -x^2=3x

The zeros of -x^2=3x are x=-3,x=0

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- x^{2} = 3 x

x = - 3, x = 0

Solution steps

- x^{2} = 3 x

Move

3 x

to the left side

- x^{2} - 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

(- 3)^{2} - 4 (- 1) \cdot 0 = 3

x_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3}{2 ( - 1 )}, x_{2} = \frac{- ( - 3 ) - 3}{2 ( - 1 )}

x = \frac{- ( - 3 ) + 3}{2 ( - 1 )} : - 3

x = \frac{- ( - 3 ) - 3}{2 ( - 1 )} : 0

The solutions to the quadratic equation are:

x = - 3, x = 0

\frac{1}{2} x^{2} - 8 = 0

2 e^{- x} - 1 > 0

4 k + 2 (3 k + 8) < 3 k + 10 - 8

a^{2} + 6 a + 8

4 ∣ 5 x ∣ + 3 = 27

What are the solutions to the equation -x^2=3x ?
The solutions to the equation -x^2=3x are x=-3,x=0
Find the zeros of -x^2=3x
The zeros of -x^2=3x are x=-3,x=0