What is factor 3x^4+23x^3+62x^2+62x+20 ?

The solution to factor 3x^4+23x^3+62x^2+62x+20 is (x+1)(3x+2)(x^2+6x+10)

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factor 3x^4+23x^3+62x^2+62x+20

factor

3 x^{4} + 23 x^{3} + 62 x^{2} + 62 x + 20

(x + 1) (3 x + 2) (x^{2} + 6 x + 10)

Solution steps

3 x^{4} + 23 x^{3} + 62 x^{2} + 62 x + 20

Use the rational root theorem

= (x + 1) \frac{3 x ^{4} + 23 x ^{3} + 62 x ^{2} + 62 x + 20}{x + 1}

\frac{3 x ^{4} + 23 x ^{3} + 62 x ^{2} + 62 x + 20}{x + 1} = 3 x^{3} + 20 x^{2} + 42 x + 20

= (x + 1) (3 x^{3} + 20 x^{2} + 42 x + 20)

Factor

3 x^{3} + 20 x^{2} + 42 x + 20 : (3 x + 2) (x^{2} + 6 x + 10)

= (x + 1) (3 x + 2) (x^{2} + 6 x + 10)

(t + 5)^{2} - 13 (t + 5) + 42 = 0

\frac{a ^{18}}{a ^{- 6}}

12 \cdot \frac{1}{8}

(- x y^{3}) (4 x^{2} y)

620 x - 2 x^{2} = 300 x + 8480

What is factor 3x^4+23x^3+62x^2+62x+20 ?
The solution to factor 3x^4+23x^3+62x^2+62x+20 is (x+1)(3x+2)(x^2+6x+10)